Subversion Repositories programming

/* Copyright: Ira W. Snyder

 * Start Date: 2005-11-28

 * End Date:

 * License: Public Domain

 *

 * Changelog Follows:

 * 2005-11-28

 * - Implement eval_euler() and eval_trapezoid().

 *

 * 2005-11-29

 * - Implement eval_romberg() and eval_simpson().

 *

 */

#include <cmath>

#include <cstdlib>

#include <cstdio>

#include <iostream>

using namespace std;

/**

 * The function given in the Project #5 Handout.

 * This is 1 + x^28

 *

 * @param x the point at which to evaluate the function

 */

float func (float x)

{

    return 1.0 + pow (x, 28);

}

/**

 * Evaluate the integral of the function given, over the interval given,

 * using the Euler method.

 *

 * @param a the lower bound of the integral

 * @param b the upper bound of the integral

 * @param n the number of intervals to use

 * @param f the function to evaluate

 */

float eval_euler (const float a, const float b, const int n, float(*f)(float))

{

    const float h = (b - a) / n;

    float answer = 0.0, xi = 0.0;

    int i = 0;

    for (i=0; i<=n; i++)

    {

        xi = a + (i * h);

        answer += f(xi);

    }

    return h * answer;

}

/**

 * Evaluate the integral of the function given, over the interval given,

 * using the trapezoid method.

 *

 * @param a the lower bound of the integral

 * @param b the upper bound of the integral

 * @param n the number of intervals to use

 * @param f the function to evaluate

 */

float eval_trapezoid (const float a, const float b, const int n, float(*f)(float))

{

    const float h = (b - a) / n;

    float answer = 0.0, xi_last = 0.0, xi_now = 0.0;

    int i = 0;

    xi_last = a + (i * h); // i = 0 here

    for (i=1; i<=n; i++)

    {

        xi_now = a + (i * h);

        answer += (f (xi_last) + f (xi_now) * (xi_now - xi_last));

        xi_last = xi_now; // shift xi's

    }

    return answer;

}

/**

 * Evaluate the integral of the function given, over the interval given,

 * using the Romberg method.

 *

 * This is directly based on the pseudocode on Pg 223-224 of the textbook.

 *

 * @param a the lower bound of the integral

 * @param b the upper bound of the integral

 * @param n the number of intervals to use

 * @param f the function to evaluate

 */

float eval_romberg (const float a, const float b, const int n, float(*f)(float))

{

    float R[n+1][n+1];

    int i, j, k;

    float h, sum;

    h = b - a;

    R[0][0] = (h/2.0) * (f(a) + f(b));

    for (i=1; i<=n; i++)

    {

        h = h/2.0;

        sum = 0.0;

        for (k=1; k<=(pow(2.0, i) - 1); k+=2)

            sum = sum + f(a + k * h);

        R[i][0] = (1.0/2.0) * R[i-1][0] + sum * h;

        for (j=1; j<=i; j++)

            R[i][j] = R[i][j-1] + (R[i][j-1] - R[i-1][j-1]) / (pow(4.0, j) - 1);

    }

    return R[n][n];

}

/**

 * Evaluate the integral of the function given, over the interval given,

 * using the Simpson method.

 *

 * This is derived from the formula on Pg 237-238

 *

 * @param a the lower bound of the integral

 * @param b the upper bound of the integral

 * @param n the number of intervals to use

 * @param f the function to evaluate

 */

float eval_simpson (const float a, const float b, const int n, float(*f)(float))

{

    const float h = (b - a) / n;

    float sum1=0.0, sum2=0.0;

    int i;

    /* Get the first sum in the formula on Pg 238 */

    for (i=1, sum1=0.0; i<=n/2; i++)

        sum1 += f (a + (2 * i - 1) * h);

    sum1 *= 4;

    /* Get the second sum in the formula on Pg 238 */

    for (i=1, sum2=0.0; i<=(n-2)/2; i++)

        sum2 += f (a + 2 * i * h);

    sum2 *= 2;

    /* Add it all together, and return it */

    return (h / 3.0) * ((f(a) + f(b)) + sum1 + sum2);

}

int main (void)

{

    const float a = 0.0;

    const float b = 3.0;

    int n = 0;

    return 0;

}